निवडीसाठी माहितीपत्रकाच्या 500 प्रति छापण्यासाठी उपलब्ध असलेल्या किंमतींच्या दोन रचना उपलब्ध आहेत. त्या पुढील प्रमाणे :
X: संख्येचा विचार न करता प्रत्येक माहितीपत्रकाची समान किंमत विचारात घेणे.
Y: सुरुवातीला निश्चित केलेली किंमत विचारात घेऊन नंतर प्रत्येक माहितीपत्रकासाठी "X" रचनेपेक्षा कमी किंमत विचारात घेणे.
वरीलप्रमाणे सर्वात कमी खर्चिक किंमत रचना निश्चित करण्यासाठी पुढे दिलेल्या माहितीसंचातील एकाची निवड करा.

The correct answer is Option D (The number of brochures for which total bill will be same by both available structures X and Y.).

Key Points:
• Mathematical & Logical Analysis:
• Structure X: Total Cost = C_X(n) = k * n, which is a straight line through the origin with slope k.
• Structure Y: Total Cost = C_Y(n) = F + m * n, where F is a fixed setup cost and m < k is the marginal cost per brochure.
• The two cost lines intersect at exactly one break-even quantity n₀, where C_X(n₀) = C_Y(n₀):
• For n < n₀, Structure X is cheaper because the fixed cost F dominates.
• At n = n₀, both cost structures yield the exact same total bill.
• For n > n₀, Structure Y is cheaper because its marginal cost m is lower than k.
• Thus, knowing simply the number of brochures for which the total bill is identical (n₀) is sufficient: if 500 > n₀, Structure Y is cheaper; if 500 < n₀, Structure X is cheaper.
• Hence, option (4) is completely sufficient and is the correct answer.
• Key Takeaway: The single intersection point (break-even quantity) between a proportional cost and a fixed-plus-variable cost determines which is cheaper for any given volume.