A, B, C, D, E, F, G आणि H असे आठ मित्र वर्तुळाकार बसलेले आहेत. सर्वांची तोंडे वर्तुळ मध्याकडे आहेत. A, B च्या डावीकडे तिसऱ्या स्थानी व F च्या उजव्या बाजूला दुसऱ्या स्थानी बसलेला आहे. D हा A किंवा B च्या बाजूला बसत नाही. C व G नेहमी एकमेकांजवळ बसतात. H हा D च्या बाजूला बसत नाही. C हा B च्या बाजूला बसत नाही.
पत्ते खेळण्यासाठी त्यांनी चार जणांचा एक, असे दोन गट तयार केले. प्रत्येक गटात, एक सोडून एक असे सदस्य घेण्यात आलेत. खालीलपैकी कोणता समूह, अशा प्रकारे तयार झालेला गट असू शकणार नाही ?

The correct answer is Option D (AFDB).

Key Points:
• Let 8 positions on the circle numbered 1 to 8 clockwise:
• Let B be at position 1. Facing center, Left is clockwise.
• A is 3rd to left of B A is at position 4.
• A is 2nd to the right of F F is at position 2.
• D cannot sit adjacent to A (positions 3, 5) or B (positions 8, 2). Thus, D must be at position 6.
• H never sits next to D, so H cannot be at 5 or 7. Unoccupied positions: 3, 5, 7, 8. Thus, H is at position 8.
• C and G sit next to each other. Available adjacent spots are positions 5 and 7 (or 3 isn't adjacent to another empty spot). Thus positions 5 and 7 are occupied by C and G.
• Since C does not sit next to B (B is at 1, neighbors 8 and 2), and D is at 6, positions 5 and 7 are adjacent to D and H.
• E takes the remaining spot, position 3.
• Notice the two alternate groups of 4 members each:
• Group 1 (positions 1, 3, 5, 7): B, E, C/G, C/G
• Group 2 (positions 2, 4, 6, 8): F, A, D, H (containing A, F, D, H)
• Examining options: Alternate groups can be formed by A, G, E, F or C, B, D, H depending on initial relative placement. But A, F, D, B has both A and F (positions 4 and 2) along with B (position 1) and D (position 6). Since B and F sit adjacent to each other (1 and 2), they CANNOT be part of the same alternate group!
• Therefore, AFDB cannot be a group formed by alternate persons. Option 4 is the correct answer.
• Key Takeaway: Since B and F sit adjacent to each other, they cannot both belong to an alternate 4-person group, making AFDB impossible.