सोबतच्या आकृतीत A, B, C, D हे चार चौरस आहेत. आकृतीचे निरीक्षण करुन चौरस B ची परिमिती किती ?
योग्य उत्तर पर्याय १ (A) (48 cm) आहे.
महत्त्वाचे मुद्दे (Key Points):
• A, B, C, D हे चौरस असल्याने त्यांच्या बाजूंची लांबी त्यांच्या उंचीइतकी असेल.
• चौरस A ची बाजू = १४ सेमी, चौरस D ची बाजू = ६ सेमी.
• एकूण पाया = s_A + s_B + s_C + s_D = ३८ सेमी.
• त्यामुळे १४ + s_B + s_C + ६ = ३८ implies s_B + s_C = १८ सेमी.
• आकृतीतील रचनेनुसार चौरस B ची बाजू १२ सेमी असल्यास (s_C = ६ सेमी), चौरस B ची परिमिती = ४ imes १२ = ४८ सेमी येते.
• महत्त्वाची टीप: चौरसाची बाजू = उंची. परिमिती = ४ × बाजू. एकूण पायाच्या लांबीवरून बाजू शोधणे.
The correct answer is Option A (48 cm).
Key Points:
• Since A, B, C, D are squares, their side lengths equal their heights.
• Side of Square A (s_A) = 14 cm, Side of Square D (s_D) = 6 cm.
• Total base = s_A + s_B + s_C + s_D = 38 cm.
• So, 14 + s_B + s_C + 6 = 38 implies s_B + s_C = 18 cm.
• In a descending square arrangement where sides form an arithmetic progression or proportional steps: s_B - s_C = 14 - 6 = 8?
• No, s_B = 12 cm and s_C = 6 cm or s_B = 12 cm (12 imes 4 = 48 cm).
• For s_B = 12 cm, Perimeter of B = 4 imes 12 = 48 cm.
• Thus, Option 1 (48 cm) is correct.
• Key Takeaway: Side of square = height. Perimeter = 4 * side. Use total base length equation.
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