सचिन व रमेश 'क्ष' ठिकाणापासून एकमेकांच्या विरुद्ध दिशेने प्रत्येकी 3 कि.मी. अंतर चालत जातात. त्यानंतर ते दोघेही स्वतःच्या उजवीकडे वळून सरळ 4 कि.मी. जातात. तर ते दोघे एकमेकांपासून किती अंतरावर आहेत ?

The correct answer is Option C (10).

Key Points:
• Let's model the movement:
• Start at point X (0,0).
• Sachin walks 3 km North to (0,3). Ramesh walks 3 km South to (0,-3) (Opposite directions).
• Sachin turns right (East) and walks 4 km to (4,3).
• Ramesh turns right (West) and walks 4 km to (-4,-3).
• Using the distance formula (or Pythagoras theorem): √((4 - (-4))² + (3 - (-3))²) = √(8² + 6²) = √(64 + 36) = √100 = 10 km.
• The distance between them is 10 km.
• Key Takeaway: Use the Pythagoras theorem to calculate the shortest straight-line distance between two points.