1.50 मीटर अंतरावर एक याप्रमाणे 27 मुलांना क्रिडांगणावर ओळीत उभे केले आहे. यातील ओळीच्या एका टोकापासून क्रमाने उभी असलेली दोन व ओळीत 14 व्या व 17 व्या क्रमांकावर उभी असलेली दोन अशी चार मुले आपापल्या जागा सोडून निघून गेली. उरलेल्या मुलांनी स्वतःच्या जागा बदलल्या नाहीत. तर आता ओळीच्या टोकाला असलेल्या मुलांच्या दरम्यानचे अंतर किती ?

The correct answer is Option B (36 meters).

Key Points:
• Linear Arrangement and Distance Calculation:
• Step-by-step mathematical calculation:
• 1. Let the 27 original positions be indexed P₁, P₂, P₃, ..., P₂₇.
• 2. The distance between any two adjacent initial positions is 1.50 m.
• 3. Two children from one end leave: without loss of generality, let positions P₁ and P₂ be vacated.
• 4. Two intermediate children at positions P₁₄ and P₁₇ also leave.
• 5. Since the remaining children do not shift their positions, the child at the frontmost remaining end is now at position P₃, and the child at the opposite end remains untouched at position P₂₇.
• 6. The number of intervals between P₃ and P₂₇ is:
• Intervals = 27 - 3 = 24
• 7. Each interval measures 1.50 m. Therefore, total distance between the new ends is:
• Distance = 24 × 1.50 = 36 meters
• Matches Option (2) exactly.
• Key Takeaway: Distance between positions 3 and 27 with 1.5m spacing is (27-3) × 1.5 = 24 × 1.5 = 36 m.